6-4(x+3)=2(x+1)

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Solution for 6-4(x+3)=2(x+1) equation: 



6-4(x+3)=2(x+1)

We move all terms to the left:

6-4(x+3)-(2(x+1))=0

We multiply parentheses

-4x-(2(x+1))-12+6=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

-4x-(2x+2)-6=0

We get rid of parentheses

-4x-2x-2-6=0

We add all the numbers together, and all the variables

-6x-8=0

We move all terms containing x to the left, all other terms to the right

-6x=8

x=8/-6

x=-1+1/3

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