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3(x-2)=-6-(12-5x)
We move all terms to the left:
3(x-2)-(-6-(12-5x))=0
We add all the numbers together, and all the variables
3(x-2)-(-6-(-5x+12))=0
We multiply parentheses
3x-(-6-(-5x+12))-6=0
We calculate terms in parentheses: -(-6-(-5x+12)), so:We get rid of parentheses
-6-(-5x+12)
determiningTheFunctionDomain -(-5x+12)-6
We get rid of parentheses
5x-12-6
We add all the numbers together, and all the variables
5x-18
Back to the equation:
-(5x-18)
3x-5x+18-6=0
We add all the numbers together, and all the variables
-2x+12=0
We move all terms containing x to the left, all other terms to the right
-2x=-12
x=-12/-2
x=+6
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