5(x+1)-2(-3x-5)=10-(3-2x)

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Solution for 5(x+1)-2(-3x-5)=10-(3-2x) equation: 



5(x+1)-2(-3x-5)=10-(3-2x)

We move all terms to the left:

5(x+1)-2(-3x-5)-(10-(3-2x))=0

We add all the numbers together, and all the variables

5(x+1)-2(-3x-5)-(10-(-2x+3))=0

We multiply parentheses

5x+6x-(10-(-2x+3))+5+10=0



We calculate terms in parentheses: -(10-(-2x+3)), so:

10-(-2x+3)

determiningTheFunctionDomain
-(-2x+3)+10

We get rid of parentheses

2x-3+10

We add all the numbers together, and all the variables

2x+7

Back to the equation:

-(2x+7)



We add all the numbers together, and all the variables

11x-(2x+7)+15=0

We get rid of parentheses

11x-2x-7+15=0

We add all the numbers together, and all the variables

9x+8=0

We move all terms containing x to the left, all other terms to the right

9x=-8

x=-8/9

x=-8/9

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