6-4(a+1)=2(4a-3)=

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Solution for 6-4(a+1)=2(4a-3)= equation: 



6-4(a+1)=2(4a-3)=

We move all terms to the left:

6-4(a+1)-(2(4a-3))=0

We multiply parentheses

-4a-(2(4a-3))-4+6=0



We calculate terms in parentheses: -(2(4a-3)), so:

2(4a-3)

We multiply parentheses

8a-6

Back to the equation:

-(8a-6)



We add all the numbers together, and all the variables

-4a-(8a-6)+2=0

We get rid of parentheses

-4a-8a+6+2=0

We add all the numbers together, and all the variables

-12a+8=0

We move all terms containing a to the left, all other terms to the right

-12a=-8

a=-8/-12

a=2/3

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