(4x-6)+(X+10)+(X+12)=180

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Solution for (4x-6)+(X+10)+(X+12)=180 equation: 



(4x-6)+(x+10)+(x+12)=180

We move all terms to the left:

(4x-6)+(x+10)+(x+12)-(180)=0

We get rid of parentheses

4x+x+x-6+10+12-180=0

We add all the numbers together, and all the variables

6x-164=0

We move all terms containing x to the left, all other terms to the right

6x=164

x=164/6

x=27+1/3

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