6-4(4+x)=8x-2(3x+5)

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Solution for 6-4(4+x)=8x-2(3x+5) equation: 



6-4(4+x)=8x-2(3x+5)

We move all terms to the left:

6-4(4+x)-(8x-2(3x+5))=0

We add all the numbers together, and all the variables

-4(x+4)-(8x-2(3x+5))+6=0

We multiply parentheses

-4x-(8x-2(3x+5))-16+6=0



We calculate terms in parentheses: -(8x-2(3x+5)), so:

8x-2(3x+5)

We multiply parentheses

8x-6x-10

We add all the numbers together, and all the variables

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

-4x-(2x-10)-10=0

We get rid of parentheses

-4x-2x+10-10=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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