3(4c-5)=c=50

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Solution for 3(4c-5)=c=50 equation: 



3(4c-5)=c=50

We move all terms to the left:

3(4c-5)-(c)=0

We add all the numbers together, and all the variables

-1c+3(4c-5)=0

We multiply parentheses

-1c+12c-15=0

We add all the numbers together, and all the variables

11c-15=0

We move all terms containing c to the left, all other terms to the right

11c=15

c=15/11

c=1+4/11

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