6-3(c+2)=12

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Solution for 6-3(c+2)=12 equation: 



6-3(c+2)=12

We move all terms to the left:

6-3(c+2)-(12)=0

We add all the numbers together, and all the variables

-3(c+2)-6=0

We multiply parentheses

-3c-6-6=0

We add all the numbers together, and all the variables

-3c-12=0

We move all terms containing c to the left, all other terms to the right

-3c=12

c=12/-3

c=-4

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