4z2+24z+36=0.

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Solution for 4z2+24z+36=0. equation: 



4z^2+24z+36=0.

a = 4; b = 24; c = +36;
Δ = b2-4ac
Δ = 242-4·4·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{-24}{8}=-3$

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