1/(x+1)-2/(x-1)=3

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Solution for 1/(x+1)-2/(x-1)=3 equation: 



1/(x+1)-2/(x-1)=3

We move all terms to the left:

1/(x+1)-2/(x-1)-(3)=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x-1)!=0

We move all terms containing x to the left, all other terms to the right

x!=1

x∈R



We calculate fractions


(1*(x-1))/((x+1)*(x-1))+(-2x-2)/((x+1)*(x-1))-3=0



We calculate terms in parentheses: +(1*(x-1))/((x+1)*(x-1)), so:

1*(x-1))/((x+1)*(x-1)

We multiply all the terms by the denominator


1*(x-1))

Back to the equation:

+(1*(x-1)))





We calculate terms in parentheses: +(-2x-2)/((x+1)*(x-1)), so:

-2x-2)/((x+1)*(x-1)

We multiply all the terms by the denominator


-2x*((x+1)*(x-1)-2)

Back to the equation:

+(-2x*((x+1)*(x-1)-2))

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