6-3(4k+1)=3-(10-8k)

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Solution for 6-3(4k+1)=3-(10-8k) equation: 



6-3(4k+1)=3-(10-8k)

We move all terms to the left:

6-3(4k+1)-(3-(10-8k))=0

We add all the numbers together, and all the variables

-3(4k+1)-(3-(-8k+10))+6=0

We multiply parentheses

-12k-(3-(-8k+10))-3+6=0



We calculate terms in parentheses: -(3-(-8k+10)), so:

3-(-8k+10)

determiningTheFunctionDomain
-(-8k+10)+3

We get rid of parentheses

8k-10+3

We add all the numbers together, and all the variables

8k-7

Back to the equation:

-(8k-7)



We add all the numbers together, and all the variables

-12k-(8k-7)+3=0

We get rid of parentheses

-12k-8k+7+3=0

We add all the numbers together, and all the variables

-20k+10=0

We move all terms containing k to the left, all other terms to the right

-20k=-10

k=-10/-20

k=1/2

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