If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12t-8.3t^2=0
a = -8.3; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-8.3)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-8.3}=\frac{-24}{-16.6} =1+5.2857142857143/11.857142857143 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-8.3}=\frac{0}{-16.6} =0 $
| 3(n-8)=21 | | 5t+10=20 | | X+30+(x-20)=180 | | 20-(2.25-x)=5.50 | | 5x-1=9+7x | | (x+7)+(x+3)+(x+20)=180 | | 5.126=4x | | 5a+9=3a+1 | | 8y-5=3(2×y) | | 230=-16t^2+150t | | 7x+25x-8=90 | | 3x+18=117 | | 7x+1/2x+9=4/5 | | -3y-7.8=-10.2 | | 6y-1.9=10.7 | | 5-9y=-22 | | -2(3v-4)=28 | | 4x+6+6x+6=52 | | 10-3x=25-2x | | 4-(2x+3)=7. | | 5x=09+2x | | (7y+4)/(y+2)=-4/3 | | x^2=5(x-1) | | 5×y=48 | | z–12=1 | | F(x)=2x⁵-6x³+8x⁵-5 | | 1.6=0.8m | | -17=-7x+4(x-5) | | x/9-7=5 | | 7z+3/3-2z=1/3 | | 1x+(-8)=5x-6 | | 2+1/4x=11 |