6-3(4-t)=3+7(t+1)

Solution for 6-3(4-t)=3+7(t+1) equation:

6-3(4-t)=3+7(t+1)

We move all terms to the left:

6-3(4-t)-(3+7(t+1))=0

We add all the numbers together, and all the variables

-3(-1t+4)-(3+7(t+1))+6=0

We multiply parentheses

3t-(3+7(t+1))-12+6=0


We calculate terms in parentheses: -(3+7(t+1)), so:

3+7(t+1)

determiningTheFunctionDomain
7(t+1)+3

We multiply parentheses

7t+7+3

We add all the numbers together, and all the variables

7t+10

Back to the equation:

-(7t+10)


We add all the numbers together, and all the variables

3t-(7t+10)-6=0

We get rid of parentheses

3t-7t-10-6=0

We add all the numbers together, and all the variables

-4t-16=0

We move all terms containing t to the left, all other terms to the right

-4t=16

t=16/-4

t=-4