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20-5(1-x)=1+3(5x-1)
We move all terms to the left:
20-5(1-x)-(1+3(5x-1))=0
We add all the numbers together, and all the variables
-5(-1x+1)-(1+3(5x-1))+20=0
We multiply parentheses
5x-(1+3(5x-1))-5+20=0
We calculate terms in parentheses: -(1+3(5x-1)), so:We add all the numbers together, and all the variables
1+3(5x-1)
determiningTheFunctionDomain 3(5x-1)+1
We multiply parentheses
15x-3+1
We add all the numbers together, and all the variables
15x-2
Back to the equation:
-(15x-2)
5x-(15x-2)+15=0
We get rid of parentheses
5x-15x+2+15=0
We add all the numbers together, and all the variables
-10x+17=0
We move all terms containing x to the left, all other terms to the right
-10x=-17
x=-17/-10
x=1+7/10
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