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6-2v=4-2(2v+4)
We move all terms to the left:
6-2v-(4-2(2v+4))=0
We calculate terms in parentheses: -(4-2(2v+4)), so:We get rid of parentheses
4-2(2v+4)
determiningTheFunctionDomain -2(2v+4)+4
We multiply parentheses
-4v-8+4
We add all the numbers together, and all the variables
-4v-4
Back to the equation:
-(-4v-4)
-2v+4v+4+6=0
We add all the numbers together, and all the variables
2v+10=0
We move all terms containing v to the left, all other terms to the right
2v=-10
v=-10/2
v=-5
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