16+8(2-2)=7z+1

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Solution for 16+8(2-2)=7z+1 equation: 



16+8(2-2)=7z+1

We move all terms to the left:

16+8(2-2)-(7z+1)=0

We add all the numbers together, and all the variables

-(7z+1)+16+80=0

We add all the numbers together, and all the variables

-(7z+1)+96=0

We get rid of parentheses

-7z-1+96=0

We add all the numbers together, and all the variables

-7z+95=0

We move all terms containing z to the left, all other terms to the right

-7z=-95

z=-95/-7

z=13+4/7

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