6-2r+1=2r-5(r-2)

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Solution for 6-2r+1=2r-5(r-2) equation: 



6-2r+1=2r-5(r-2)

We move all terms to the left:

6-2r+1-(2r-5(r-2))=0

We add all the numbers together, and all the variables

-2r-(2r-5(r-2))+7=0



We calculate terms in parentheses: -(2r-5(r-2)), so:

2r-5(r-2)

We multiply parentheses

2r-5r+10

We add all the numbers together, and all the variables

-3r+10

Back to the equation:

-(-3r+10)



We get rid of parentheses

-2r+3r-10+7=0

We add all the numbers together, and all the variables

r-3=0

We move all terms containing r to the left, all other terms to the right

r=3

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