3(k+2)=4k+10

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Solution for 3(k+2)=4k+10 equation: 



3(k+2)=4k+10

We move all terms to the left:

3(k+2)-(4k+10)=0

We multiply parentheses

3k-(4k+10)+6=0

We get rid of parentheses

3k-4k-10+6=0

We add all the numbers together, and all the variables

-1k-4=0

We move all terms containing k to the left, all other terms to the right

-k=4

k=4/-1

k=-4

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