6-2(x+3)=20

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Solution for 6-2(x+3)=20 equation: 



6-2(x+3)=20

We move all terms to the left:

6-2(x+3)-(20)=0

We add all the numbers together, and all the variables

-2(x+3)-14=0

We multiply parentheses

-2x-6-14=0

We add all the numbers together, and all the variables

-2x-20=0

We move all terms containing x to the left, all other terms to the right

-2x=20

x=20/-2

x=-10

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