6-2(4x+1)=4x-2(2x+6)

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Solution for 6-2(4x+1)=4x-2(2x+6) equation: 



6-2(4x+1)=4x-2(2x+6)

We move all terms to the left:

6-2(4x+1)-(4x-2(2x+6))=0

We multiply parentheses

-8x-(4x-2(2x+6))-2+6=0



We calculate terms in parentheses: -(4x-2(2x+6)), so:

4x-2(2x+6)

We multiply parentheses

4x-4x-12

We add all the numbers together, and all the variables

-12

Back to the equation:

-(-12)



We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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