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4(2x+4)=6(3x-1/3)
We move all terms to the left:
4(2x+4)-(6(3x-1/3))=0
We add all the numbers together, and all the variables
4(2x+4)-(6(+3x-1/3))=0
We multiply parentheses
8x-(6(+3x-1/3))+16=0
We multiply all the terms by the denominator
8x*3))-(6(+3x-1+16*3))=0
We add all the numbers together, and all the variables
8x*3))-(6(3x+47))=0
We add all the numbers together, and all the variables
8x*3))-(6(3x=0
Wy multiply elements
24x^2=0
a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{48}=0$
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