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6-(3-x)=x+4(2x+3)
We move all terms to the left:
6-(3-x)-(x+4(2x+3))=0
We add all the numbers together, and all the variables
-(-1x+3)-(x+4(2x+3))+6=0
We get rid of parentheses
1x-(x+4(2x+3))-3+6=0
We calculate terms in parentheses: -(x+4(2x+3)), so:We add all the numbers together, and all the variables
x+4(2x+3)
We multiply parentheses
x+8x+12
We add all the numbers together, and all the variables
9x+12
Back to the equation:
-(9x+12)
x-(9x+12)+3=0
We get rid of parentheses
x-9x-12+3=0
We add all the numbers together, and all the variables
-8x-9=0
We move all terms containing x to the left, all other terms to the right
-8x=9
x=9/-8
x=-1+1/8
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