10x-3(2-x)=5+(x-7)

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Solution for 10x-3(2-x)=5+(x-7) equation:



10x-3(2-x)=5+(x-7)
We move all terms to the left:
10x-3(2-x)-(5+(x-7))=0
We add all the numbers together, and all the variables
10x-3(-1x+2)-(5+(x-7))=0
We multiply parentheses
10x+3x-(5+(x-7))-6=0
We calculate terms in parentheses: -(5+(x-7)), so:
5+(x-7)
determiningTheFunctionDomain (x-7)+5
We get rid of parentheses
x-7+5
We add all the numbers together, and all the variables
x-2
Back to the equation:
-(x-2)
We add all the numbers together, and all the variables
13x-(x-2)-6=0
We get rid of parentheses
13x-x+2-6=0
We add all the numbers together, and all the variables
12x-4=0
We move all terms containing x to the left, all other terms to the right
12x=4
x=4/12
x=1/3

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