6-(2z-2)=3-3z

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Solution for 6-(2z-2)=3-3z equation: 



6-(2z-2)=3-3z

We move all terms to the left:

6-(2z-2)-(3-3z)=0

We add all the numbers together, and all the variables

-(2z-2)-(-3z+3)+6=0

We get rid of parentheses

-2z+3z+2-3+6=0

We add all the numbers together, and all the variables

z+5=0

We move all terms containing z to the left, all other terms to the right

z=-5

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