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1-(x+3)=-3(x-2)
We move all terms to the left:
1-(x+3)-(-3(x-2))=0
We get rid of parentheses
-x-(-3(x-2))-3+1=0
We calculate terms in parentheses: -(-3(x-2)), so:We add all the numbers together, and all the variables
-3(x-2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
-1x-(-3x+6)-2=0
We get rid of parentheses
-1x+3x-6-2=0
We add all the numbers together, and all the variables
2x-8=0
We move all terms containing x to the left, all other terms to the right
2x=8
x=8/2
x=4
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