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6+x=7/2x-2
We move all terms to the left:
6+x-(7/2x-2)=0
Domain of the equation: 2x-2)!=0We get rid of parentheses
x∈R
x-7/2x+2+6=0
We multiply all the terms by the denominator
x*2x+2*2x+6*2x-7=0
Wy multiply elements
2x^2+4x+12x-7=0
We add all the numbers together, and all the variables
2x^2+16x-7=0
a = 2; b = 16; c = -7;
Δ = b2-4ac
Δ = 162-4·2·(-7)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{78}}{2*2}=\frac{-16-2\sqrt{78}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{78}}{2*2}=\frac{-16+2\sqrt{78}}{4} $
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