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6+5(x-3)=3-5(x-9)
We move all terms to the left:
6+5(x-3)-(3-5(x-9))=0
We multiply parentheses
5x-(3-5(x-9))-15+6=0
We calculate terms in parentheses: -(3-5(x-9)), so:We add all the numbers together, and all the variables
3-5(x-9)
determiningTheFunctionDomain -5(x-9)+3
We multiply parentheses
-5x+45+3
We add all the numbers together, and all the variables
-5x+48
Back to the equation:
-(-5x+48)
5x-(-5x+48)-9=0
We get rid of parentheses
5x+5x-48-9=0
We add all the numbers together, and all the variables
10x-57=0
We move all terms containing x to the left, all other terms to the right
10x=57
x=57/10
x=5+7/10
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