-24=-6x(4+x)5

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Solution for -24=-6x(4+x)5 equation:



-24=-6x(4+x)5
We move all terms to the left:
-24-(-6x(4+x)5)=0
We add all the numbers together, and all the variables
-(-6x(x+4)5)-24=0
We calculate terms in parentheses: -(-6x(x+4)5), so:
-6x(x+4)5
We multiply parentheses
-30x^2-120x
Back to the equation:
-(-30x^2-120x)
We get rid of parentheses
30x^2+120x-24=0
a = 30; b = 120; c = -24;
Δ = b2-4ac
Δ = 1202-4·30·(-24)
Δ = 17280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{17280}=\sqrt{576*30}=\sqrt{576}*\sqrt{30}=24\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-24\sqrt{30}}{2*30}=\frac{-120-24\sqrt{30}}{60} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+24\sqrt{30}}{2*30}=\frac{-120+24\sqrt{30}}{60} $

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