6+4x+7x=3(6x+-12)+-4(x+-6)

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Solution for 6+4x+7x=3(6x+-12)+-4(x+-6) equation: 



6+4x+7x=3(6x+-12)+-4(x+-6)

We move all terms to the left:

6+4x+7x-(3(6x+-12)+-4(x+-6))=0

We add all the numbers together, and all the variables

4x+7x-(3(6x-12)+-4(x-6))+6=0

We add all the numbers together, and all the variables

11x-(3(6x-12)+-4(x-6))+6=0

We use the square of the difference formula

11x-(3(6x-12)-4(x-6))+6=0



We calculate terms in parentheses: -(3(6x-12)-4(x-6)), so:

3(6x-12)-4(x-6)

We multiply parentheses

18x-4x-36+24

We add all the numbers together, and all the variables

14x-12

Back to the equation:

-(14x-12)



We get rid of parentheses

11x-14x+12+6=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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