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4(2y-3)=7(y-2)
We move all terms to the left:
4(2y-3)-(7(y-2))=0
We multiply parentheses
8y-(7(y-2))-12=0
We calculate terms in parentheses: -(7(y-2)), so:We get rid of parentheses
7(y-2)
We multiply parentheses
7y-14
Back to the equation:
-(7y-14)
8y-7y+14-12=0
We add all the numbers together, and all the variables
y+2=0
We move all terms containing y to the left, all other terms to the right
y=-2
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