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6+4/5n=9/10n
We move all terms to the left:
6+4/5n-(9/10n)=0
Domain of the equation: 5n!=0
n!=0/5
n!=0
n∈R
Domain of the equation: 10n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
4/5n-(+9/10n)+6=0
We get rid of parentheses
4/5n-9/10n+6=0
We calculate fractions
40n/50n^2+(-45n)/50n^2+6=0
We multiply all the terms by the denominator
40n+(-45n)+6*50n^2=0
Wy multiply elements
300n^2+40n+(-45n)=0
We get rid of parentheses
300n^2+40n-45n=0
We add all the numbers together, and all the variables
300n^2-5n=0
a = 300; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·300·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*300}=\frac{0}{600} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*300}=\frac{10}{600} =1/60 $
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