3(z-2)=7+1

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Solution for 3(z-2)=7+1 equation: 



3(z-2)=7+1

We move all terms to the left:

3(z-2)-(7+1)=0

We add all the numbers together, and all the variables

3(z-2)-8=0

We multiply parentheses

3z-6-8=0

We add all the numbers together, and all the variables

3z-14=0

We move all terms containing z to the left, all other terms to the right

3z=14

z=14/3

z=4+2/3

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