6+4(3u-4)=-5(2u-1)+4u

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Solution for 6+4(3u-4)=-5(2u-1)+4u equation: 



6+4(3u-4)=-5(2u-1)+4u

We move all terms to the left:

6+4(3u-4)-(-5(2u-1)+4u)=0

We multiply parentheses

12u-(-5(2u-1)+4u)-16+6=0



We calculate terms in parentheses: -(-5(2u-1)+4u), so:

-5(2u-1)+4u

We add all the numbers together, and all the variables

4u-5(2u-1)

We multiply parentheses

4u-10u+5

We add all the numbers together, and all the variables

-6u+5

Back to the equation:

-(-6u+5)



We add all the numbers together, and all the variables

12u-(-6u+5)-10=0

We get rid of parentheses

12u+6u-5-10=0

We add all the numbers together, and all the variables

18u-15=0

We move all terms containing u to the left, all other terms to the right

18u=15

u=15/18

u=5/6

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