6+3x=2(-x+3)-35

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Solution for 6+3x=2(-x+3)-35 equation: 



6+3x=2(-x+3)-35

We move all terms to the left:

6+3x-(2(-x+3)-35)=0

We add all the numbers together, and all the variables

3x-(2(-1x+3)-35)+6=0



We calculate terms in parentheses: -(2(-1x+3)-35), so:

2(-1x+3)-35

We multiply parentheses

-2x+6-35

We add all the numbers together, and all the variables

-2x-29

Back to the equation:

-(-2x-29)



We get rid of parentheses

3x+2x+29+6=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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