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6+3(x-1)=5(x+1)
We move all terms to the left:
6+3(x-1)-(5(x+1))=0
We multiply parentheses
3x-(5(x+1))-3+6=0
We calculate terms in parentheses: -(5(x+1)), so:We add all the numbers together, and all the variables
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
3x-(5x+5)+3=0
We get rid of parentheses
3x-5x-5+3=0
We add all the numbers together, and all the variables
-2x-2=0
We move all terms containing x to the left, all other terms to the right
-2x=2
x=2/-2
x=-1
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