20(5-x)+100=204-2(x+3)

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Solution for 20(5-x)+100=204-2(x+3) equation: 



20(5-x)+100=204-2(x+3)

We move all terms to the left:

20(5-x)+100-(204-2(x+3))=0

We add all the numbers together, and all the variables

20(-1x+5)-(204-2(x+3))+100=0

We multiply parentheses

-20x-(204-2(x+3))+100+100=0



We calculate terms in parentheses: -(204-2(x+3)), so:

204-2(x+3)

determiningTheFunctionDomain
-2(x+3)+204

We multiply parentheses

-2x-6+204

We add all the numbers together, and all the variables

-2x+198

Back to the equation:

-(-2x+198)



We add all the numbers together, and all the variables

-20x-(-2x+198)+200=0

We get rid of parentheses

-20x+2x-198+200=0

We add all the numbers together, and all the variables

-18x+2=0

We move all terms containing x to the left, all other terms to the right

-18x=-2

x=-2/-18

x=1/9

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