6+3(x+2)=10-(4+3x)

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Solution for 6+3(x+2)=10-(4+3x) equation: 



6+3(x+2)=10-(4+3x)

We move all terms to the left:

6+3(x+2)-(10-(4+3x))=0

We add all the numbers together, and all the variables

3(x+2)-(10-(3x+4))+6=0

We multiply parentheses

3x-(10-(3x+4))+6+6=0



We calculate terms in parentheses: -(10-(3x+4)), so:

10-(3x+4)

determiningTheFunctionDomain
-(3x+4)+10

We get rid of parentheses

-3x-4+10

We add all the numbers together, and all the variables

-3x+6

Back to the equation:

-(-3x+6)



We add all the numbers together, and all the variables

3x-(-3x+6)+12=0

We get rid of parentheses

3x+3x-6+12=0

We add all the numbers together, and all the variables

6x+6=0

We move all terms containing x to the left, all other terms to the right

6x=-6

x=-6/6

x=-1

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