6(x+4)-10=5(x+3)+1

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Solution for 6(x+4)-10=5(x+3)+1 equation: 



6(x+4)-10=5(x+3)+1

We move all terms to the left:

6(x+4)-10-(5(x+3)+1)=0

We multiply parentheses

6x-(5(x+3)+1)+24-10=0



We calculate terms in parentheses: -(5(x+3)+1), so:

5(x+3)+1

We multiply parentheses

5x+15+1

We add all the numbers together, and all the variables

5x+16

Back to the equation:

-(5x+16)



We add all the numbers together, and all the variables

6x-(5x+16)+14=0

We get rid of parentheses

6x-5x-16+14=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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