6+3(4u-3)=-2(6u-3)+6u

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Solution for 6+3(4u-3)=-2(6u-3)+6u equation: 



6+3(4u-3)=-2(6u-3)+6u

We move all terms to the left:

6+3(4u-3)-(-2(6u-3)+6u)=0

We multiply parentheses

12u-(-2(6u-3)+6u)-9+6=0



We calculate terms in parentheses: -(-2(6u-3)+6u), so:

-2(6u-3)+6u

We add all the numbers together, and all the variables

6u-2(6u-3)

We multiply parentheses

6u-12u+6

We add all the numbers together, and all the variables

-6u+6

Back to the equation:

-(-6u+6)



We add all the numbers together, and all the variables

12u-(-6u+6)-3=0

We get rid of parentheses

12u+6u-6-3=0

We add all the numbers together, and all the variables

18u-9=0

We move all terms containing u to the left, all other terms to the right

18u=9

u=9/18

u=1/2

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