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-1(x)=x2+4x-1
We move all terms to the left:
-1(x)-(x2+4x-1)=0
We add all the numbers together, and all the variables
-(+x^2+4x-1)-1x=0
We get rid of parentheses
-x^2-4x-1x+1=0
We add all the numbers together, and all the variables
-1x^2-5x+1=0
a = -1; b = -5; c = +1;
Δ = b2-4ac
Δ = -52-4·(-1)·1
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{29}}{2*-1}=\frac{5-\sqrt{29}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{29}}{2*-1}=\frac{5+\sqrt{29}}{-2} $
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