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-2(x)=x2-5x+2
We move all terms to the left:
-2(x)-(x2-5x+2)=0
We add all the numbers together, and all the variables
-(+x^2-5x+2)-2x=0
We get rid of parentheses
-x^2+5x-2x-2=0
We add all the numbers together, and all the variables
-1x^2+3x-2=0
a = -1; b = 3; c = -2;
Δ = b2-4ac
Δ = 32-4·(-1)·(-2)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-1}{2*-1}=\frac{-4}{-2} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+1}{2*-1}=\frac{-2}{-2} =1 $
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