x-0.5(10-8x)=3(2x-4)+x

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Solution for x-0.5(10-8x)=3(2x-4)+x equation: 



x-0.5(10-8x)=3(2x-4)+x

We move all terms to the left:

x-0.5(10-8x)-(3(2x-4)+x)=0

We add all the numbers together, and all the variables

x-0.5(-8x+10)-(3(2x-4)+x)=0

We multiply parentheses

x+4x-(3(2x-4)+x)-5=0



We calculate terms in parentheses: -(3(2x-4)+x), so:

3(2x-4)+x

We add all the numbers together, and all the variables

x+3(2x-4)

We multiply parentheses

x+6x-12

We add all the numbers together, and all the variables

7x-12

Back to the equation:

-(7x-12)



We add all the numbers together, and all the variables

5x-(7x-12)-5=0

We get rid of parentheses

5x-7x+12-5=0

We add all the numbers together, and all the variables

-2x+7=0

We move all terms containing x to the left, all other terms to the right

-2x=-7

x=-7/-2

x=3+1/2

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