6+2b=2(b+3)

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Solution for 6+2b=2(b+3) equation: 



6+2b=2(b+3)

We move all terms to the left:

6+2b-(2(b+3))=0



We calculate terms in parentheses: -(2(b+3)), so:

2(b+3)

We multiply parentheses

2b+6

Back to the equation:

-(2b+6)



We get rid of parentheses

2b-2b-6+6=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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