5(x-7)-6(x-11)+7(x-10)=2

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Solution for 5(x-7)-6(x-11)+7(x-10)=2 equation: 



5(x-7)-6(x-11)+7(x-10)=2

We move all terms to the left:

5(x-7)-6(x-11)+7(x-10)-(2)=0

We multiply parentheses

5x-6x+7x-35+66-70-2=0

We add all the numbers together, and all the variables

6x-41=0

We move all terms containing x to the left, all other terms to the right

6x=41

x=41/6

x=6+5/6

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