6+2(3h-2)=4(1+h)

Solution for 6+2(3h-2)=4(1+h) equation:

6+2(3h-2)=4(1+h)

We move all terms to the left:

6+2(3h-2)-(4(1+h))=0

We add all the numbers together, and all the variables

2(3h-2)-(4(h+1))+6=0

We multiply parentheses

6h-(4(h+1))-4+6=0


We calculate terms in parentheses: -(4(h+1)), so:

4(h+1)

We multiply parentheses

4h+4

Back to the equation:

-(4h+4)


We add all the numbers together, and all the variables

6h-(4h+4)+2=0

We get rid of parentheses

6h-4h-4+2=0

We add all the numbers together, and all the variables

2h-2=0

We move all terms containing h to the left, all other terms to the right

2h=2

h=2/2

h=1