7(3x+5)-1(4x-2)=2

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Solution for 7(3x+5)-1(4x-2)=2 equation: 



7(3x+5)-1(4x-2)=2

We move all terms to the left:

7(3x+5)-1(4x-2)-(2)=0

We multiply parentheses

21x-1(4x-2)+35-2=0

We add all the numbers together, and all the variables

21x-1(4x-2)+33=0

We move all terms containing x to the left, all other terms to the right

21x-1(4x-2)=-33

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