6+2(2u-5)=-7(2u-2)+6u

Solution for 6+2(2u-5)=-7(2u-2)+6u equation:

6+2(2u-5)=-7(2u-2)+6u

We move all terms to the left:

6+2(2u-5)-(-7(2u-2)+6u)=0

We multiply parentheses

4u-(-7(2u-2)+6u)-10+6=0


We calculate terms in parentheses: -(-7(2u-2)+6u), so:

-7(2u-2)+6u

We add all the numbers together, and all the variables

6u-7(2u-2)

We multiply parentheses

6u-14u+14

We add all the numbers together, and all the variables

-8u+14

Back to the equation:

-(-8u+14)


We add all the numbers together, and all the variables

4u-(-8u+14)-4=0

We get rid of parentheses

4u+8u-14-4=0

We add all the numbers together, and all the variables

12u-18=0

We move all terms containing u to the left, all other terms to the right

12u=18

u=18/12

u=1+1/2