22+n=3n-4(1-6n)

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Solution for 22+n=3n-4(1-6n) equation: 



22+n=3n-4(1-6n)

We move all terms to the left:

22+n-(3n-4(1-6n))=0

We add all the numbers together, and all the variables

n-(3n-4(-6n+1))+22=0



We calculate terms in parentheses: -(3n-4(-6n+1)), so:

3n-4(-6n+1)

We multiply parentheses

3n+24n-4

We add all the numbers together, and all the variables

27n-4

Back to the equation:

-(27n-4)



We get rid of parentheses

n-27n+4+22=0

We add all the numbers together, and all the variables

-26n+26=0

We move all terms containing n to the left, all other terms to the right

-26n=-26

n=-26/-26

n=1

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