6+2(-2k+1)=-(k-5)

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Solution for 6+2(-2k+1)=-(k-5) equation: 



6+2(-2k+1)=-(k-5)

We move all terms to the left:

6+2(-2k+1)-(-(k-5))=0

We multiply parentheses

-4k-(-(k-5))+2+6=0



We calculate terms in parentheses: -(-(k-5)), so:

-(k-5)

We get rid of parentheses

-k+5

We add all the numbers together, and all the variables

-1k+5

Back to the equation:

-(-1k+5)



We add all the numbers together, and all the variables

-4k-(-1k+5)+8=0

We get rid of parentheses

-4k+1k-5+8=0

We add all the numbers together, and all the variables

-3k+3=0

We move all terms containing k to the left, all other terms to the right

-3k=-3

k=-3/-3

k=1

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