3(1+4b)=-(-8b-5)+2b

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Solution for 3(1+4b)=-(-8b-5)+2b equation: 



3(1+4b)=-(-8b-5)+2b

We move all terms to the left:

3(1+4b)-(-(-8b-5)+2b)=0

We add all the numbers together, and all the variables

3(4b+1)-(-(-8b-5)+2b)=0

We multiply parentheses

12b-(-(-8b-5)+2b)+3=0



We calculate terms in parentheses: -(-(-8b-5)+2b), so:

-(-8b-5)+2b

We add all the numbers together, and all the variables

2b-(-8b-5)

We get rid of parentheses

2b+8b+5

We add all the numbers together, and all the variables

10b+5

Back to the equation:

-(10b+5)



We get rid of parentheses

12b-10b-5+3=0

We add all the numbers together, and all the variables

2b-2=0

We move all terms containing b to the left, all other terms to the right

2b=2

b=2/2

b=1

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